Discussion

Explanation:

Total combinations when a die is rolled twice = 6 × 6 = 36

Case 1: The first roll = 1
The second roll = (2, 3, 4, 5, 6)
∴ Favourable outcomes = 5

Case 2: The first roll = 2
The second roll = (3, 4, 5, 6)
∴ Favourable outcomes = 4

Case 3: The first roll = 3
The second roll = (4, 5, 6)
∴ Favourable outcomes = 3

Case 4: The first roll = 4
The second roll = (5, 6)
∴ Favourable outcomes = 2

Case 5: The first roll = 5
The second roll = (6)
∴ Favourable outcomes = 1

Hence, the number of favourable outcomes = 5 + 4 + 3 + 2 + 1 = 15

Therefore, the probability = 15/36 

Alternately,
Let us calculate the number of ways a different number comes up both the die = 6 × 5 = 30.

Out of these 30 ways, in half of these first die will have higher number and in other half second die will have higher number.

∴ Probability that second die has higher number = 15/36.

Hence, option (c).

» Your doubt will be displayed only after approval.


Doubts


Feedback

Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.


© 2024 | All Rights Reserved | Apti4All