Discussion

Explanation:

​​​​​​​

∆BAA’ ~ ∆BCC’
BCBA=CC'AA'   …(1)

Also, ∆ABB’ ~ ∆ACC’
ACAB=CC'BB'    …(2)

Adding (1) and (2) we get

AC+BCAB=CC'AA'+CC'BB' 

⇒ 1 = CC'AA'+CC'BB'

1CC'=1AA'+1BB'

1CC'=160'+140 = 124

∴ CC’ = 24.

Hence, option (c).

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