Two alcohol solutions, A and B, are mixed in the proportion 1 : 3 by volume. The volume of the mixture is then doubled by adding solution A such that the resulting mixture has 72% alcohol. If solution A has 60% alcohol, then the percentage of alcohol in solution B is
Explanation:
Given, A and B are mixed in the ratio 1 : 3
Let 10 liters of A and 30 liters of B is mixed initially i.e., total 40 liters solution.
Now volume is double by adding 40 liters of A.
∴ In the solution A = 10 + 40 = 50 liters and B = 30 liters
Concentration of alcohol in this 80-liter solution = 72%
Let the alcohol concentration in B = b%
∴ 80 × 72% = 50 × 60% + 30 × b%
⇒ 576 = 300 + 30b
⇒ b = 92%
Hence, option (a).
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