Discussion

Explanation:

Assuming, k = 14a = 36b = 84c

⇒ 14 = k1/a

⇒ 36 = 62 = k1/b or 6 = k1/2b 

⇒ 84 = k1/c

We know, 84 = 6 × 14

⇒ k1/c = k1/2b × k1/a

⇒ k1/c – 1/a = k1/2b

1c-1a=12b

2b1c-1a = 1

Hence, 6b1c-1a = 3

Hence, 3.

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