Discussion

Explanation:

Let x meters and y meters be the radius of the outer and the inner circles respectively and O be their center.
In right angled Δ OCB,

CB2 = OB2 - OC2

⇒ 9 = x2 – y2
⇒ (x + y) ( x – y) = 9 × 1
As x and y are integers, therefore, x + y = 9 and x – y = 1.
Thus, x = 5.
Hence, radius of the outer circle is 5 meters.

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