Discussion

Explanation:

If the numbers are a, b, c and d such that a < b < c < d, then from statement I, we get (d – c) > (b – a).
So we can say, (d + a) > (b + c) or (d + a) + (d + a) > (b + c) + (d + a). Dividing both the sides by 4, we get

(d+a)2>(a+b+c+d)4.

This shows that the average of the largest and the smallest of four numbers is indeed greater than the average of all the 4 numbers. Hence, we can answer the question using first statement only.

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