Discussion

Explanation:

Case 1: The 2nd letter is m and the 3rd letter is e:

The 1st letter may be any of the 4 remaining vowels (i.e. different from e)

Number of possible 3 letter combinations = 4

Case 2: The 2nd letter is n and the 3rd letter is e:

The 1st letter may be any of the 5 vowels.

Number of possible 3 letter combinations = 5

Case 3: The 2nd letter is p and the 3rd letter is e:

The 1st letter will be the same as the 3rd letter.

Number of possible 3 letter combinations = 1 (i.e. ‘epe’)

∴ Total number of possible 3 letter combinations = 4 + 5 + 1 = 10

Hence, option (c).

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