Discussion

Question:

For what values of ‘a’ is le(a² – 3a, a – 3) < 0?

Explanation:

We can work this on the above lines. E.g.
(a) a > 3. Let a = 4. So le(a² – 3a, a – 3) = le(4, 1) = 1 > 0.
(b) 0 < a < 3. Let a = 2. So le(a² – 3a, a – 3) = le(–2, –1) = –2 < 0.
(c) a < 0. Let a = –1. So le(a² – 3a, a – 3) = le(4, –4) = –4 < 0.

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