Discussion

Question:

For what values of ‘a’ is me(a² – 3a, a – 3) < 0?

Explanation:

Let us verify by taking arbitrary values of a in the range specified.
(a) a > 3. Let a = 4.
So me(a² – 3a, a – 3) = me(4, 1) = 4 > 0.
(b) 0 < a < 3. Let a = 2.
So me(a² – 3a, a – 3) = me(–2, –1) = –1 < 0.
(c) a < 0. Let a = –1.
So me(a² – 3a, a – 3) = me(4, –4) = 4 > 0.
(d) a = 3, me(a² – 3a, a – 3) = me(0, 0) = 0.

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