Discussion

Question:

Two positive integers differ by 4 and sum of their reciprocals is $\frac{10}{21}$ . Then one of the numbers is

Explanation:

Let one of the numbers be x. So the other number would be (x + 4).

According to the question, we have $\frac{1}{x} + \frac{1}{(x + 4)} =$ 21 or x = 3.

Hint:

Please note that the sum of reciprocals is basically $= \frac{(S u m o f t h e i n t e g e r s)}{(P r o d u c t o f t h e i n t e g e r s)}$ .

So we have to find two integers whose sum is 10 and whose product is 21.

So x + (x + 4) = 10 or x = 3.

Hence, option (a).

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