Discussion

Explanation:

First series: (S1) = x, y, x2, z, x + 20

Second series: (S2) = a1, a2, a3, a4

Now a1 = y – x, a2x2 - y, a3 = z - xand a4 = x + 20 – z

a2 – a1 = 30 gives 3x – 4y = 60 ... (1)

a4 – a3 = 30 gives 3x – 4z = 20 ... (2)

and a4 – a2 = 60 gives x – 2z + 2y = 80 ... (3)

Solving these equations we get the values of x = 100, y = 60, z = 70

∴ S1 is 100, 60, 50, 70, 120

S2 is –40, –10, 20, 50.

Hence, option (c).

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