Discussion

Explanation:

HCF of 60, 84 and 108 is 12. Hence, 12 students should be seated in each room. So for subject A we would require 6012 = 5 rooms, for subject B we would require 8412 = 7 rooms and for subject C we would require 10812 = 9 rooms. Hence, minimum
number of rooms required to satisfy our condition = (5 + 7 + 9) = 21 rooms.

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