If A collected 54 coins and B collected two more coins than twice the number of coins collected by C, then the number of coins collected by B could be
Explanation:
If A has collected 54 coins, the remaining three of them should collect (100 – 54) = 46 coins between themselves. Let us assume that C has collected 10 coins. So B will collect (2 × 10) + 2 = 22. So A will collect (46 – 10 – 22) = 14 coins, which is a possible combination.
Let us now assume that C picks up 12 coins. So B should pick up (2 × 12) + 2 = 26. So A will have to collect (46 – 12 – 26) = 8 coins. This combination is not possible. It can be concluded that C cannot pick up more than 10 coins and hence B has to pick up 22 coins to satisfy the given condition.
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