Three circles, each of radius 20, have centres at P, Q and R. Further, AB = 5, CD = 10 and EF = 12. What is the perimeter of ΔPQR?
Explanation:
PQ = PE + FQ – FE = radius of circle 1 + radius of circle 2 – FE = 20 + 20 – 12 = 28 Similarly, QR = 20 + 20 – CD = 40 – 10 = 30 and PR = 20 + 20 – AB = 40 – 5 = 35 So perimeter of ΔPQR = 28 + 30 + 35 = 93
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