Discussion

Explanation:

f (x,y) = |x + y|      This is always positive
F(f (x,y)) = − f (x,y) = −|x + y|      This is always negative
G(f (x,y)) = − F(f (x,y)) = − (−|x + y|) = |x + y|     This is always positive.

ƒ(G(ƒ(1, 0)), ƒ(F (ƒ(1,2)), G(ƒ(1, 2))))
= ƒ(G(ƒ(1, 0)), ƒ(3, − 3))
= ƒ(G(ƒ(1, 0)), 0)
= ƒ(−1, 0) = 1.

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