A motorbike leaves point A at 1 pm and moves towards point B at a uniform speed. A car leaves point B at 2 pm and moves towards point A at a uniform speed which is double that of the motorbike. They meet at 3:40 pm at a point which is 168 km away from A. What is the distance, in km, between A and B?
Explanation:
Motorbike travels 168 kms from 1 pm till 3:40 pm i.e. in 2 hours 40 mins = 83 hours.
⇒ Speed of motorbike = 1688/3 = 63 kmph
∴ Speed of Car = 2 × Speed of Motorbike = 2 × 63 = 126 km/hr
Now as the car travels for 1 hour 40 minutes.
Distance travelled by the car = 126 × 53 or 210 km
Distance between A and B = Distance travelled by Motorbike + Distance travelled by Car
= 168 + 210 = 378 km
Hence, option (b).
» Your doubt will be displayed only after approval.
Help us build a Free and Comprehensive Preparation portal for various competitive exams by providing us your valuable feedback about Apti4All and how it can be improved.