Discussion

Explanation:

Suppose the base exchange rates of A, B and C w.r.t L are 100m, 120m and m respectively.

Therefore we have the following:

​​​​​​​​​​​​​​

Given: The outlet received 88000 units of L by selling A. Therefore the number of units of A sold 

=88000110 m=800m

From point 3, the number of units of L received by selling B = 95 × 88000 = 158400

Therefore the number of units of B sold = 158400132 m=1200m

From points 5 and 6, the number of units of A bought = 800 + 800m

Therefore, the number of units of L paid to buy A

= 95m 800+800m = 76000 (1 + m)

From point 2, the number of units of L paid to buy B = 

35 × 76000 (1 + m) = 45600 (1 + m)

Therefore the number of units of B bought = 45600(1+m)114 m=400+400m

From points 5 and 6,

1200m=400+400m. Solving for m, m = 2

Therefore we have the following

​​​​​​​​​​​​​​

If the number of units of C sold = x, from points 5 and 6, the number of units of C bought = x + 3000.

Therefore, we get, 1.9(x+3000)=2.2x or solving for x, x = 19000.

Using the value of m, we get the following table for the number of units of A, B and C bought and sold.

​​​​​​​​​​​​​​

The buying exchange rate of C w.r.t. L on that day was 1.90

Hence, option (c).

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