Discussion

Explanation:

70% of 20 = 14

Qualified candidate score 14 or more marks in two or more sections.

Composite scores of few students:

Chetna: 2(19) + 4 + 12 = 54

Ester: 2(12) + 18 + 16 = 58

Falak: 2(15) + 7 + 10 = 47

From (6), Jatin scored 20 marks in DI. Therefore, his Composite score is 2(20) + 16 + 14 = 70

Therefore, Indu’s Composite score = 60

If Indu scored 20 marks in DI, her score in GA = 60 – 2(20) – 8 = 12.

In this case, Indu scored less than 70% in WE and GA. But from (4) Indu was recruited. Therefore, this case is not valid. This means she must have scored 100% marks in GA i.e., 20 marks in GA.

∴ indu's marks (out of 20) in DI = 60-8-202

=322 = 16

From (5), Danish and Harini also scored 20 marks in GA.

Therefore, his Composite score = 2(8) + 15 + 20 = 51

From (2), Ajay must have scored more than 18 marks. Assuming his score in WE as 19, composite score would be 2(8) + 19 + 16 = 51. This cannot be true as Danish’s composite score was 51. Thus, Ajay’s score in WE = 20 and his composite score 2(8) + 20 + 16 = 52.

Bala, Chetna and Falak scored less than 70% marks in at least two sections and hence were disqualified.

From (4), Geeta had the lowest score. Maximum composite score of Harini = 2(5) + 20 + 20 = 50

Ajay(52), Danish(51), Ester(58), Indu(60) and Jatin(70) are definitely qualified.

So, Ester(58), Indu(60) and Jatin(70) were top three scorers. Geeta must have scored more than 52 marks. Therefore marks scored by her in WE ≥ 53 – 2(14) − 6 i.e., marks scored by her in WE ≥ 19

If she had scored 20 marks in WE, her composite marks would be 2(14) + 20 + 6 = 54

But Chetna’s composite score = 54. So, Geeta’s marks in WE = 19 and her composite score = 53

Thus we have

​​​​​​​

‘a’ denotes marks of Harini in WE while ‘d’ denote marks of Bala in DI.

Jatin’s composite score = 70 and Danish’s composite score = 51

Thus, statement 1 is true.

Indu’s score in DI = 16 and Chetna’s score in DI = 19

Thus, statement 2 is true.

Jatin’s score in GA = 14 and Indu’s score in GA = 20

Thus, statement 3 is false.

Hence, option (a).

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