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Explanation:

Let PA, FB and SC denote the lamp post, the father and the son respectively and let D denote the point where the shadows of the father’s and son’s heads are incident.

ΔBFD ~ ΔCSD

BFCS=FDSD

1.80.9=FDSD

FDSD = 2

∴ FD = 2 × SD

Let SD = FS = x m

ΔAPD ~ ΔBFD

APBF=PDFD

61.8=2.1+2x2x

20x3=2.1+2x

14x3=2.1

∴ x = 0.45 m

∴ The son is standing 0.45 m away from the father.

Hence, option (d).

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