Discussion

Explanation:

Solution:

Let the speed of the train be St and the speed of the CAT be Sc.

Case 1:

The CAT runs towards the train.

dSt=3x8Sc

3x8×StSc=d ...(i)

Case 2:

The CAT runs away from the train.

d+xSt=5x8Sc

d=5x8×StSC-x ...(ii)

Equating (i) and (ii),

3x8×StSc=5x8×StSc-x38x×StSc=5x8×StSc-x38 StSc=58 StSc-1

∴ St : Sc = 4 : 1

Hence, option (a).

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