The ratio of the areas of the two quadrangles ABCD and DEFG is
Explanation:
Area of trapezium ABCD = 12 BC (CD + AB) Also BC = 2CD, AB = BC = 2CD
Area of trapezium ABCD = 12 × CD (CD + 2DC) = 3CD2
Area of trapezium DEFG = 12 EO(EF + DG)
EO = CD
EF = CD
DG = CH + HK + KL = CD + CD + CD2=52CD
Area of trapezium DEFG = 12×CDCD+52CD=12×CD7CD2=7CD24...(ii)
Ratio of ABCD : DEFG = 12 : 7
Hence, option (c).
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