Discussion

Explanation:

Area of trapezium ABCD = 12 BC (CD + AB)
Also BC = 2CD, AB = BC = 2CD

Area of trapezium ABCD = 12 × CD (CD + 2DC) = 3CD2

Area of trapezium DEFG = 12 EO(EF + DG)

EO = CD

EF = CD

DG = CH + HK + KL = CD + CD + CD2=52CD

Area of trapezium DEFG = 12×CDCD+52CD=12×CD7CD2=7CD24...(ii) 

Ratio of ABCD : DEFG = 12 : 7

Hence, option (c).

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