On a straight road XY, 100 metres in length, 5 stones are kept beginning from the end X. The distance between two adjacent stones is 2 metres. A man is asked to collect the stones one at a time and put at the end Y. What is the distance covered by him?
Explanation:
The first stone is kept at 'X' and the subsequent stones are equidistant from each other, i.e. 2 metres.
∴ The total distance covered by the man to keep all the stones at Y = 100 + 2 × (98 + 96 + 94 + 92) = 100 + 2 × (380) = 860 metres
Hence, option (c).
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