Discussion

Explanation:

x² + 5y² + z² = 4xy + 2yz

∴ x² + 4y² + y² + z² – 4xy – 2yz = 0

∴ (x² + 4y² – 4xy) + (y² – 2yz + z²) = 0

∴ (x – 2y)² + (y – z)² = 0            …(i)

As per equation (i),

∴ (x – 2y)² = 0 and (y – z)² = 0

∴ x = 2y and y = z

Hence, option (d).

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