Discussion

Explanation:

Route taken by Haripriya: S → R → B

Time taken from S → R:
Travel time = 10 × 2 = 20 mins
Stoppage time = 9 × 1 = 9 mins
Total time = 20 + 9 = 29 mins

Similarly, Time taken from R → B: 7 × 3 + 7 = 28 mins

In the north-south direction, the first train from A arrives at R at time = 6 am + (3 × 3) + (2 × 1) mins = 6:11 am.
Since R is a junction so this train will halt for 2 minutes at R and leave at 6:13.
Every 15 minutes, a train starts from A in the north-south direction.
The last train that leaves A will be at 12:00 am and it will leave R at 12:13 am, so Haripriya must reach R till 12:13 am.
If she catches this train from R at 12:13, she will reach B by 12:13 + 28 = 12:41 am.

Travelling time between S and R = (10 × 2) + (9 × 1) = 29
So Haripriya must board the train at S by (12:13 - 29 =) 11:44 pm
In the east-west direction, the first train from N arrives at S at time = 6 am + (6 × 2) + (5 × 1) = 6:17 am.
Since S is a junction so this train will halt for 2 minutes at S and leave at 6:19.
Every 10 minutes, a train starts from N in the east-west direction.
Therefore, Haripriya should board the train which leaves S at 11:39.

​​​​​​​Hence, option (c).

» Your doubt will be displayed only after approval.


Doubts


Anshu said (2023-08-01 13:02:50)

11:39 kese possible hai 11:35 hi to Anna chaiye

Reply from Admin:

The first train which will leave S towards R will be at 6:19 am. After this there will be a train leaving S for R every 10 mins (east-west direction).

The next trains will be at 6:29, 6:39, 6: 49, 7:59. 8:09, 8:19 and so on.

Since Harsita has to leave S latest by 11:44 pm, she needs to board the train on or before 11:44 pm. The train which leaves S before 11:44 will leave at 11:39.


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