Discussion

Explanation:

Priya can go from T to S via R or V.

Case 1: T – R – S
The first train to depart T will be at (6 am + 9 + 2 + 2 =) 6:13 am.
∴ Now a train will depart T every 15 minutes, hence the train which Priya can catch for T → R is at 10:28.

Time taken to reach R = 12 + 3 = 15 mins.
∴ Priya reaches R at 10:43 am.

The first train to depart R will be at (6 am + 8 + 3 + 2 =) 6:13 am.
∴ Now a train will depart R every 10 minutes, hence the train which Priya can catch for R → S is at 10:43 itself.

Time taken to reach S = 20 + 9 = 29 mins.
∴ Priya reaches S at 11:12 am.

Case 2: T – S – R
The first train to depart T will be at (6 am + 8 + 3 + 2 =) 6:13 am.
∴ Now a train will depart T every 10 minutes, hence the train which Priya can catch for T → V is at 10:33 itself.

Now time taken from T → V is 29 mins and time taken from V → S is 15 mins.
Even if Priya does not have to wait at V she can S latest by 10:33 am + 29 + 15 = 11:17 am.

∴ Priya can reach S latest by 11:12 am.

Hence, option (a).

» Your doubt will be displayed only after approval.


Doubts


Sevean said (2023-08-24 08:08:28)

The first train to depart T will be 6:13 am, therefore train which Priya can catch for T-->R is at 10:28am. How did we calculated from 6:30 to 10:28 am..can someone explain??

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solution updated for your query.


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