The number of ways of distributing 20 identical balloons among 4 children such that each child gets some balloons but no child gets an odd number of balloons, is
Explanation:
Let the number of balloons each child gets is 2a, 2b, 2c and 2d respectively. a, b, c, d > 0
⇒ 2a + 2b + 2c + 2d = 20 ⇒ a + b + c + d = 10
Number of combinations of a, b, c and d such that a, b, c and d > 0 = (10-4)+4-1C4-1 = 9C3 = 84.
Hence, 84.
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