Discussion

Explanation:

Given, a + 2b = 6.
⇒ a + b = 6 - b 

∴ (a + b) will be maximum when b is least. Least value of b can be 0, since b cannot be negative.
⇒ (a + b)max = 6

∴ (a + b) will be minimum when b is highest. Highest value of b can be 3, since a cannot be negative.
⇒ (a + b)min = 3

⇒ Average of highest and lowest values of (a + b) = 3+62 = 4.5

Hence, option (b).

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