What is the chance that the total number of widgets delivered in a day is 260 units and the route ends at Bikrampore?
Explanation:
Demand A – 50 (40%); 70 (60%) B – 40 (30%); 60 (70%) C – 70 (30%); 100 (70%) D – 30 (40%); 50 (60%)
For route to end at B, B should have least demand i.e., 40.
Total demand is 260, hence demand at other cities should be higher of the two values. ∴ Demand at A = 70 (60%) Demand at B = 40 (30%) Demand at C = 100 (70%) Demand at D = 50 (60%)
∴ Required possibility = 60% × 30% × 70% × 60% = 0.6 × 0.3 × 0.7 × 0.6 = 0.0756 = 7.56%
Hence, option (a).
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