The ratio of ‘metal 1’ and ‘metal 2’ in Alloy ‘A’ is 3:4. In Alloy ‘B’ same metals are mixed in the ratio 5:8. If 26 kg of Alloy ‘B’ and 14 kg of Alloy ‘A’ are mixed then find out the ratio of ‘metal 1’ and ‘metal 2’ in the new Alloy.
Explanation:
Ratio of metal 1 and metal 2 in alloy A = 3 : 4
In 14 kg, there will be 3/7 × 14 = 6 kg of metal 1 and 4/7 × 14 = 8 kg of metal 2.
Similarly, alloy B contains 10 kg and 16 kg of metal 1 and metal 2 respectively.
∴ Metal 1 content in final mixture = 6 + 10 = 16 kg
Metal 2 content in final mixture = 8 + 16 = 24 kg
∴ Required ratio = 16 : 24 ≡ 2 : 3
Hence, option (c).
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