If k is an integer and 0.0010101 × 10k is greater than 1000, what is the least possible value of k?
Explanation:
We need 0.0010101 × 10k > 1000
∴ 1010.1 × 10–6 × 10k > 1000
∴ 1010.1 × 10–6 + k > 1000
∵ 1010.1 > 1000, 10–6 + k = 1
∴ k – 6 = 0
∴ k = 6
Hence, option (c).
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