Average of A, B and C is given by
Explanation:
We need to find average of A, B and C i.e. (A + B + C)/3
The only operator that can give 3 in the denominator is “X”
Option 1 cannot be the answer, as there is no “X”.
Option 2 also cannot be the answer as X(@(/(@(/(B, A), 2), C), 3), 2) gives 2 in the denominator and not 3.
Similarly option 3 is not the answer.
Hence, option (d) must be the answer.
Option 4:
/ ( X (@ (/ (@ (B, A), 2), C), 3), 2)
=/x@/A+B2,2,c,3,2
=/(X(@((A + B), C), 3), 2)
=/xA+B+C2,3,2=/A+B+C6,2
=2(A+B+C)6=A+B+C3
Hence, option (d).
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