A jar contains a mixture of 175 ml water and 700 ml alcohol. Gopal takes out 10% of the mixture and substitutes it by water of the same amount. The process is repeated once again. The percentage of water in the mixture is now
Explanation:
Originally, the volume of alcohol = 4 times the volume of water. Therefore, original percentage of alcohol = 80% and original volume of water = 20%.
When 10% of the mixture is removed and replaced with water, the percentage of alcohol remained in the mixture
= 80%×9102 = 64.8%
Therefore the percentage of water in the mixture = (100 - 64.8)% = 35.2%.
Hence, option (c).
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