Suppose, log3x = log12y = a, where x, y are positive numbers. If G is the geometric mean of x and y, and log6G is equal to:
Explanation:
log3x = a ⇒ x = 3a.
log12y = a ⇒ y = 12a.
∴ xy = 36a and √(xy) = G = 6a.
∴ log6G = a.
Hence, option (d).
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