CAT 2002 LRDI | Previous Year CAT Paper

Answer: Option B

Explanation :

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The table given above indicates the ranks according to the annual sales-tax revenue collections of seven states from 1996-97 to 2000-01.

WB, TN and MA have the ranks 7, 2, and 1 respectively over the five years.

AP and KA change their ranks only once, in 1997-98.

∴ There are five states for which the ranks didn’t change more than once.

Hence, option (b).

Answer: Option B

Explanation :

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From the table, we see that UP and GU have changed their rankings twice (in the years1997-98 and 2000-01).

Hence, option (b).

Answer: Option D

Explanation :

In 1996-97, the percentage share of AP = $\frac{3526}{29870}$ ×100 = 11.80%

In 2000-01, the percentage share of AP = $\frac{7202}{49639}$ × 100 = 14.50%

Similarly calculating for other states, we get:

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∴ We can see that the percentage share of sales tax revenue has increased only for AP.

Hence, option (d).

Answer: Option C

Explanation :

Growth rate of tax revenue in MA for 1997-98

$=\frac{7826-7290}{7290}$ × 100

$\approx \frac{500}{7300}<10\%$

Growth rate of tax revenue in MA for 1998-99

$=\frac{8067-7826}{7826}$ × 100

$\approx \frac{200}{7800}<10\%$

Growth rate of tax revenue in MA for 1999-00

$=\frac{10284-8067}{8067}$ × 100

$\approx \frac{2000}{8000}\approx 25\%$

Growth rate of tax revenue in MA for 2000-01

$=\frac{12034-10284}{10284}$ × 100

$\approx \frac{2000}{10000}\approx 20\%$

Hence, option (c).

Answer: Option A

Explanation :

For Karnataka the increase from the year 1998-1999 to 1999-2000 and the increase from the year 1999-2000 to 2000-2001 is the same.

Increase from 1998-1999 to 1999-2000 = 4839 – 4265 = 574

Increase from 1999-2000 to 2000-2001 = 5413 – 4839 = 574

Hence, option (a).

Answer: Option C

Explanation :

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From the table, it is seen that WB, TN and MA have a consistent rank.

∴ From the given options, only Tamil Nadu has been maintaining a constant rank.

Hence, option (c).

Answer: Option B

Explanation :

The regions that produce medium quality of Crop-1 or Crop-2 are R₆, R₇, R₈, R₉ and R₁₃

The regions that produce low quality of Crop-3 or Crop-4 are R₁, R₄, R₅ and R₉

Thus, only region R₉ produces medium quality of Crop-2 and low quality of Crop-4.

Hence, option (b).

Answer: Option C

Explanation :

Option 1 is false because R₉ is a medium quality Crop-2 producing region, which does not produce high quality of Crop-3.

Option 2 is false because R₃ is a high quality Crop-1 producing region, which does not produce medium and low qualities of Crop-4.

Option 3 is true as there are exactly 5 regions (R₁, R₂, R₃, R₄ and R₁₁) and that produce Crop-3 and Crop-4 but not Crop-2.

Option 4 is false as no regions producing Crop-3 produces high quality Crop-2.

Hence, option (c).

Answer: Option C

Explanation :

Regions R₉, R₁₀ and R₁₁ produce low quality of Crop-1.

Of these, regions R₁₀ and R₁₁ also produce high quality of Crop-4 while regions R₉ and R₁₁ produce medium quality of Crop-3.

∴There are 3 low quality Crop-1 producing regions that are either high quality Crop-4 producing regions or medium quality Crop-3 producing regions.

Hence, option (c).

Answer: Option B

Explanation :

Vienna, Sofia, Tripoli, Warsaw and Lusaka lie between 10° E and 40° E.

∴ The number of cities located within 10° E and 40° E = 5

Out of these, only Lusaka is in the Southern Hemisphere.

∴ Required percentage = $\frac{1}{5}$ × 100 = 20%

Hence, option (b).

Answer: Option A

Explanation :

‘Cities’ implies that we need to refer to the ‘Capitals’ column while answering this question.

The number of cities whose names begin with a consonant and are in the Northern Hemisphere = 11

The number of cities whose names begin with a consonant and are in the Southern Hemisphere = 7

The number of cities whose names begin with a consonant and lie East of the meridian = 17

∴ The number of cities whose names begin with a consonant and are in the Northern Hemisphere exceed the cities whose names begin with a consonant and are in the Southern Hemisphere by 4.

Hence, option (a).

Answer: Option A

Explanation :

There are three countries, Argentina, Australia and Equador, which start with a vowel and are in the Southern Hemisphere.

There are two countries, Canada and Ghana, whose capitals (Ottawa and Accra) start with a vowel.

∴ The required ratio = 3 : 2

Hence, option (a).

Answer: Option A

Explanation :

Earnings per day = $\frac{\mathrm{Total} \mathrm{Earnings} \mathrm{for} \mathrm{complex} \mathrm{work}}{\mathrm{Number} \mathrm{of} \mathrm{days} \mathrm{for} \mathrm{complex} \mathrm{work}}$

Hence, we have:

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Employees numbered 2001159, 2001162, 2001165 and 2001170 have earned more than Rs. 50 per day in complex operation.

∴ Number of employees = 4

Hence, option (a).

Answer: Option D

Explanation :

80% of 25 = 20

∴ Total attendance should be more than 20 and total earning should be more than 600.

There are 7 employees (2001147, 2001159, 2001170, 2001171, 2001174, 2001177 and 2001180) who have worked for more than 20 days and whose earning is more than Rs. 600.

Hence, option (d).

Answer: Option A

Explanation :

Earnings per day in medium operations for the given options is as follows: 

Employe 2001180 ≡ $\frac{1262.79}{19}$ = Rs. 66.5

Employe 2001165 ≡ $\frac{735.72}{12.07}$ = Rs. 61

Employe 2001170 ≡ $\frac{117.46}{8.5}$ = Rs. 13.8

Employe 2001177 ≡ $\frac{726.19}{19}$ = Rs. 38.2

Hence, option (a).

Answer: Option D

Explanation :

There are 10 employees who are engaged in both complex and medium operations.

For employee 2001148:

The amount earned in Medium operations = 513.26 − 51.53 − 3 = 458.73

$\frac{51.53}{3.33}<\frac{458.73}{1.67}$

For employee 2001151:

The amount earned in Medium operations = 282.81 − 171.71 − 79.1 = 32

$\frac{171.71}{5.5}>\frac{32}{4}$

For employee 2001155:

The amount earned in Medium operations = 597.94 − 497.47 − 100.47 = 0

Hence, the average amount earned per day in Medium operations = 0/4.67 = 0

Hence, the average amount earned per day in Complex operations is more.

For employee 2001159:

$\frac{594.43}{9.67}>\frac{159.64}{13.33}$

For employee 2001162:

$\frac{472.51}{1.29}>\frac{109.73}{9.71}$

For employee 2001165:

$\frac{402.25}{5.27}>\frac{735.72}{12.07}$

For employee 2001169:

$\frac{288.48}{8.38}>\frac{6.1}{4.25}$

For employee 2001170:

$\frac{812.1}{10}>\frac{117.46}{8.5}$

For employee 2001177:

$\frac{46.56}{2}<\frac{726.19}{19}$

For employee 2001180:

$\frac{116.4}{5}<\frac{1262.79}{19}$

∴ There are 7 employees for whom per day earnings in complex operations is more than per day earnings in medium operations.

Hence, option (d).

Answer: Option C

Explanation :

Total revenue in 1999 = 3374
 
∴ 5% of the total revenue in 1999 = 0.05 × 3374 = 168.7

The operations of Spain, the Rest of Latin America, the Northern Sea and the Rest of the World are less than 168.7.

Hence, option (c).

Answer: Option B

Explanation :

Total revenues earned from 1999 to 2000 = 3374 + 5328 = 8702
5% of 8702 = 435.1

There are only two operations, the Northern Sea and Rest of the World, whose gross revenues for these two years is less than 435.1.

Hence, option (b).

Answer: Option B

Explanation :

Only North Africa and the Middle East, Argentina, the Rest of Latin America and the Far East experience a sustained increase.

∴ There are 4 regions.

Hence, option (b).

Answer: Option C

Explanation :

The average increase in income before taxes and charges from 1998 to 1999 (ignoring the loss making operations)

$=\frac{(7-31)+(341-111)+(838-94)+(97-19)+(75-26)}{5}$

= 1077/5 = 215.4

Looking at the Incomes of the various operations in 1998 and 1999, it is clear that Argentina and the Far East definitely have percentage increases of more than 400%. It is also clear that all the other operations (except North America and the Middle East) will have percentage increases less than 200%.

% Increase in North America and Middle East from 1998-99 = $\frac{341-111}{111}$ × 100 ≈ 210

Hence, option (c).

Answer: Option B

Explanation :

Consider option 1:

Profitability of Far East operations in 1998 = $\frac{10}{63}$ = 0.158

Profitability of Far East operations in 1999 = $\frac{58}{204}$ = 0.284

Profitability of Far East operations in 2000 = $\frac{189}{311}$ = 0.607

The profitability is highest for the year 2000.

∴ Option 1 is false.

Consider option 2:

Profitability of Northern Sea operations in 1998 = $\frac{24}{52}$ = 0.462

Profitability of Northern Sea operations in 1998 = $\frac{54}{65}$ = 0.831

Profitability is increased from 1998 to 1999.

∴ Option 2 is true.

Consider option 3

Profitability of Argentina operations in 1998 = $\frac{61}{187}$ = 0.326

Profitability of Northern Sea operations in 1998 = $\frac{500}{1168}$ = 0.428

Profitability has increased from 1998 to 1999.

∴ Option 3 is false.

Hence, option (b).

Answer: Option B

Explanation :

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The profitability for the given options are as given in the above table.

Spain has the best profitability.

Hence, option (b).

Answer: Option D

Explanation :

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Efficiency for all operations in 2000 is shown in the above table.

Efficiency is the least for the Rest of the World.

Hence, option (d).

Answer: Option D

Explanation :

Option 1 is true as Spain has the best efficiency in 2000.

Consider option 2:

Emergency of Far East operation in 1999 = $\frac{301}{204}\approx$ 1.5

Emergency of Far East operation in 2000 = $\frac{603}{311}\approx$ 2 

Efficiency has improved from 1999 to 2000.

∴ Option 2 is true.

Consider option 3:

Efficiency of Northern Sea operation in 1998 = $\frac{78}{52}$ = 1.5

Efficiency of Northern Sea operation in 1999 = $\frac{140}{65}$ = 2.2

Efficiency has improved from 1998 to 1999.

∴ Option 3 is true.

Consider option 4:

Option 4 is false as in the year 1998, the operations in the Rest of the World was the least efficient.

Hence, option (d).

Answer: Option B

Explanation :

The highest ratio of the percentages will be the highest average price because the multiplying factor is common for all.

∵ Average price = $\frac{\mathrm{Value} \mathrm{of} \mathrm{million} \mathrm{Euro}}{\mathrm{Volume} \mathrm{in} \mathrm{million} \mathrm{tons}}$

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∴ Switzerland has the highest average price.

Hence, option (b).

Answer: Option B

Explanation :

Distribution value of Turkey = 16% of 5760 million Euro

Distribution quantity of Turkey = 15% of 1.05 million tons

∴ Average Price = $\frac{{\displaystyle \frac{16}{100}}\times 5760\times {10}^6}{{\displaystyle \frac{15}{100}}\times 1.05\times {10}^6\times {10}^3}=\frac{16\times 5760}{15\times 1.05\times {10}^2}$ = 5.85 Euro/kg

Hence, option (b).

Answer: Option A

Explanation :

The cost of transporting one unit from refinery BD to depot AE is Rs. 0 and the cost of transporting one unit from depot AE to district AAB is also Rs. 0.

∴ The minimum cost of transporting one unit from any refinery to any district is Rs. 0.

Hence, option (a).

Answer: Option D

Explanation :

Number of ways = Six refineries × Seven depots × Nine districts

                          = 6 × 7 × 9 

                          = 378

Hence, option (d).

Answer: Option B

Explanation :

The highest cost of transportation from a refinery to the depot = Rs. 1,157.70 (BE to AE)

Cost of transportation from AE to AAF takes up the highest charge of Rs. 1,035.30

∴ The maximum cost = 1157.7 + 1035.3 = Rs. 2,193

Hence, option (b).

Answer: Option B

Explanation :

The transportation cost from refinery BD to depot AE is Rs. 0.

The transportation cost from depot AE to district AAB is also Rs. 0.

∴ The minimum cost of transportation from BD to any district is Rs. 0.

Hence, option (b).

Answer: Option D

Explanation :

The transportation cost from depot AD to district AAG = 0

The transportation cost from refinery BC to depot AD = Rs. 50.1

∴ Minimum cost of transportation from any refinery to district AAG = Rs. 50.1

Hence, option (d).

Answer: Option D

Explanation :

The cost will be minimum when the transportation from BE to AAA is through AD.

∴ The cost of transportation = 650.4 + 159 = Rs. 809.4

Hence, option (d).

Answer: Option A

Explanation :

The movement can be tabulated as below:

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Distance = $20\times \frac{1}{2}+40\times \frac{1}{4}+40\times \frac{1}{2}+100\times \frac{2}{5}+40\times \frac{1}{4}$

= 10 + 10 + 20 + 40 + 10

= 90 km

Hence, option (a).

Answer: Option B

Explanation :

The map of his movements is as shown below:

∴ The net displacement with respect to the starting point

$=\sqrt{{40}^2+{30}^2}$ = 50 km towards North-East

Hence, option (b).

Answer: Option A

Explanation :

Since only the direction of the man has changed, the total distance covered by him will still remain the same.

∴ Total distance = 90 km

Hence, option (a).

Answer: Option D

Explanation :

If instead of North, the man headed for South, the map given in the solution of the second question in the set will get inverted and flipped.

∴ He will end up south-west of his starting position, instead of north-east.

∴ He ends up at 30 km West and 40 km South of his starting point.

Hence, option (d).

Answer: Option D

Explanation :

A causes B or C, but not both.

In either case, D occurs.

F can occur only if B occurs, while E can occur only if C occurs. Since only one of B and C can occur, hence only one of F and E can occur.

Hence, option (d).

Answer: Option C

Explanation :

Consider option 1:

E occurs only if C occurs,

∴ E cannot occur because of a cause not mentioned.

Consider option 2:

E occurs only if C occurs and F occurs only if B occurs,

∴ E and F both cannot occur as a result of a cause not mentioned.

Consider option 4:

J occurs only if E or F occurs,

∴ J also cannot occur as a result of a cause not mentioned.

Consider option 3:

It is given that A causes B or C but not both,

∴ Either B or C can occur by a cause not mentioned. 

Hence, option (c).

Answer: Option A

Explanation :

The original arrangement,

The new arrangement is as per the changes described in the question,

∴ Kundan is sitting to the left of Abhishek.

Hence, option, 1.